What is the balanced net ionic equation for the following reaction: 2 NH4Cl + Ba(OH)2 = 2H2O + BaCl2 + 2 NH3
i got 2NH4^+ +2OH- = 2H2O + 2NH3
but it keeps telling me i'm wrong
Try dividing the coefficients by 2 to arrive at 1 for all of them. Please let me know if this takes care of the problem.
Well, well, well, looks like you're in a sticky situation! Don't worry, I'm here to help. Let's see if we can balance that net ionic equation for you.
First, let's break down the starting compounds into their respective ions:
NH4Cl → 2 NH4+ + Cl-
Ba(OH)2 → Ba2+ + 2 OH-
Now, let's write the molecular equation:
2 NH4+ + 2 Cl- + Ba2+ + 2 OH- → 2 H2O + BaCl2 + 2 NH3
Finally, let's write the net ionic equation by removing the spectator ions (the ones that appear on both sides of the equation and do not participate in the reaction):
2 H2O + BaCl2 + 2 NH3
And there you have it! The balanced net ionic equation is 2 H2O + BaCl2 + 2 NH3. Keep that equation handy, you never know when it might come in handy at a chemistry comedy show!
To solve this problem, let's write the balanced net ionic equation step-by-step:
Step 1: Write the complete balanced molecular equation.
2 NH4Cl + Ba(OH)2 → 2 H2O + BaCl2 + 2 NH3
Step 2: Split the soluble ionic compounds into their respective ions.
NH4Cl (NH4+ and Cl-) + Ba(OH)2 (Ba2+ and OH-) → H2O + BaCl2 + NH3 (NH3 is a weak base and does not dissociate in water)
Step 3: Write the balanced ionic equation by only including the ions that undergo changes.
2 NH4+ + 2 OH- → 2 H2O + Ba2+ + 2 Cl- + 2 NH3
Step 4: Simplify the equation by removing the spectator ions (ions that appear on both sides of the equation unchanged).
Ba2+ and Cl- are spectator ions, so they can be eliminated.
2 NH4+ + 2 OH- → 2 H2O + 2 NH3
Step 5: Divide the equation by the smallest stoichiometric coefficient to obtain the balanced net ionic equation.
The balanced net ionic equation is:
NH4+ + OH- → H2O + NH3
So, the balanced net ionic equation for the given reaction is NH4+ + OH- → H2O + NH3.
To balance the net ionic equation for the reaction: 2 NH4Cl + Ba(OH)2 = 2 H2O + BaCl2 + 2 NH3, you need to follow these steps:
1. Start by writing the balanced chemical equation for the overall reaction. The given equation is already balanced, so we have:
2 NH4Cl + Ba(OH)2 = 2 H2O + BaCl2 + 2 NH3
2. Next, write the complete ionic equation by representing all soluble compounds as separate ions:
2 NH4+ + 2 Cl- + Ba2+ + 2 OH- = 2 H2O + Ba2+ + 2 Cl- + 2 NH3
Notice that the Ba2+ and Cl- ions appear on both sides of the equation and can be canceled out. This leaves us with:
2 NH4+ + 2 OH- = 2 H2O + 2 NH3
3. Finally, write the net ionic equation by removing the spectator ions (ions that appear on both sides of the equation and don't participate directly in the reaction):
2 NH4+ + 2 OH- = 2 H2O + 2 NH3
This is the balanced net ionic equation for the given reaction. It represents the species that are actually involved in the reaction.
Now, if you got the same equation (2 NH4+ + 2 OH- = 2 H2O + 2 NH3), there might be other factors at play. Make sure to double-check your work and ensure that you have accounted for all the ions and balanced them correctly.