A robot probe drops a camera off the rim of a 245 m high cliff on Mars, where the free-fall acceleration is 3.7 m/s2.

Find the velocity with which it hits the
ground. Answer in units of m/s.

2)Find the time required for the camera to reach
the ground.
Answer in units of s.

please show work

V^2 = Vo^2 + 2gad,

V^2 = 0 + 2 * 3.7 * 245 = 1813,
V = 42.6 m/s.

2. d = 0.5at^2 = 245 m
0.5 * 3.7 * t^2 = 245,
1.85 * t^2 = 245,
f^2 = 245 / 1.85 = 132.4,

t = 11.5 s.

I don't know and nor do you cause yk why? all of us is dumb :).

To find the velocity with which the camera hits the ground, we can use the equation of motion for free-falling objects:

v = u + at

Where:
v = final velocity (the velocity at which it hits the ground)
u = initial velocity (in this case, the camera is dropped from rest, so u = 0)
a = acceleration due to gravity on Mars (given as 3.7 m/s^2)
t = time taken to reach the ground (unknown)

Using these values, the equation becomes:

v = 0 + (3.7 m/s^2) * t

Now, let's find the time required for the camera to reach the ground.

We can use the equation of motion for free-falling objects:

s = ut + (1/2)at^2

Where:
s = displacement (the height of the cliff, which is 245 m)
u = initial velocity (0 m/s)
a = acceleration due to gravity on Mars (3.7 m/s^2)
t = time taken to reach the ground (unknown)

Plugging in the given values, the equation becomes:

245 = 0 + (1/2)(3.7 m/s^2)t^2

Now, let's solve these equations to find the velocity and time.

1) To find the velocity (v):

v = 0 + (3.7 m/s^2) * t

Since the initial velocity (u) is zero, the final velocity (v) is simply:

v = 3.7 m/s^2 * t

2) To find the time (t):

245 = 0 + (1/2)(3.7 m/s^2)t^2

Rearranging the equation:

(1/2)(3.7 m/s^2)t^2 = 245

Dividing both sides by (1/2)(3.7 m/s^2):

t^2 = (2 * 245)/(1/2)(3.7 m/s^2)

t^2 = 140/1.85

Taking the square root of both sides:

t = √(140/1.85)

Simplifying the expression, we have:

t ≈ 7.297 s

Therefore, the velocity with which the camera hits the ground is approximately 3.7 m/s, and the time required for it to reach the ground is approximately 7.297 seconds.

hf=hi+vi*t -1/2 * 3.7*t^2

hf=0,hi=245, vi=0 solve for time t

vf=3.7m/s * time