A 120 kg crate on a flatbed truck is moving at 1.5 m/s2 for 65 m. What is the total work done on the crate if it's sitting horizontally at an angle of 0 degrees?
Your "moving at 1.5 m/s^2" implies an acceleration. Ideally, no work would be rewquired to keep it moving at constant velocity.
The accelerating force required is
F = ma = 180 N. Multiply that by the distance moved to get the required work.
To find the total work done on the crate, we need to calculate the force exerted on it and multiply it by the displacement.
First, we need to determine the force acting on the crate. The force can be calculated using Newton's second law:
Force = mass x acceleration
Given that the mass of the crate is 120 kg, and the acceleration is 1.5 m/s^2, we can substitute these values into the equation:
Force = 120 kg x 1.5 m/s^2 = 180 N
Next, we need to calculate the displacement. The displacement is given as 65 m.
Now, we can calculate the work done on the crate using the formula:
Work = Force x displacement x cosθ
Since the crate is sitting horizontally at an angle of 0 degrees, the cosine of 0 degrees is 1.
Therefore, the total work done on the crate is:
Work = 180 N x 65 m x cos0° = 180 N x 65 m x 1 = 11,700 J
So, the total work done on the crate is 11,700 Joules.
To find the total work done on the crate, we need to know the force exerted and the distance over which the force is applied. In this case, the crate is moving horizontally at an angle of 0 degrees, so the force exerted is equal to the force of gravity acting on the crate.
The force of gravity can be calculated using the formula F = m * g, where F is the force of gravity, m is the mass of the crate, and g is the acceleration due to gravity. In this case, the mass of the crate is given as 120 kg, and the acceleration due to gravity is approximately 9.8 m/s^2.
So, F = 120 kg * 9.8 m/s^2 = 1176 N.
Now, we need to calculate the work done over the given distance. The work done can be calculated using the formula W = F * d * cos(theta), where W is the work done, F is the force applied, d is the distance over which the force is applied, and theta is the angle between the force and the direction of motion.
In this case, the force applied is the force of gravity (1176 N), the distance over which the force is applied is given as 65 m, and the angle theta is 0 degrees since the crate is moving horizontally.
So, W = 1176 N * 65 m * cos(0) = 1176 N * 65 m * 1
Therefore, the total work done on the crate is 76,440 Joules.