physics

once a 21 kg crate is in motion on a hoizontal floor, a horizontal force of 58 N keeps the crate moving with a constant velocity.

the acceleration of gravity is 9.81 m/s^2. what is mu k , the coefficient of kinetic friction, between the crate and the floor?

  1. 8
asked by autumn
  1. The friction force equals the applied force (58N) in this no-acceleration case. They are in opposite directions, and cancel out.

    58 = M*g*muk

    Solve for muk

    posted by drwls

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