Thioacetoamide decomposes in hot water to produce hydrogen sulfide, which is the active reactant in the first step of this reaction. write balanced equation of thioacetoamide in water. Does what I have below make sense?
C2H5NS + H2O ----> H2S + C2H3NO
The reaction you have written is not balanced. Here is the balanced equation for the decomposition of Thioacetoamide in water:
C2H5NS + H2O → H2S + C2H4NO
To write the balanced equation for the decomposition of thioacetoamide (C2H5NS) in water, we need to make sure that the number of atoms of each element is the same on both sides of the equation.
The reaction is as follows:
C2H5NS + H2O → H2S + C2H3NO
To balance the equation, we can start by counting the number of atoms of each element on each side:
Carbon (C): 2 on the left, 2 on the right
Hydrogen (H): 7 on the left, 7 on the right
Nitrogen (N): 1 on the left, 1 on the right
Sulfur (S): 1 on the left, 1 on the right
Oxygen (O): 1 on the left, 1 on the right
So far, there is an equal number of atoms of each element. However, we also need to ensure that the charges are balanced. Since water (H2O) is a neutral molecule, we need to add two hydrogen ions (H+) on the left side to balance the charge:
C2H5NS + 2H2O → H2S + C2H3NO
Now, the equation is balanced both in terms of the number of atoms and the charges. As a result, the correctly balanced equation for the decomposition of thioacetoamide in water is:
C2H5NS + 2H2O → H2S + C2H3NO
Not quite.
C2H5NS + H2S ==> C2H5NO + H2S