# Physics

An 8.74-kg block slides with an initial speed of 1.52 m/s down a ramp inclined at an angle of 27.0° with the horizontal. The coefficient of kinetic friction between the block and the ramp is 0.64. Use energy conservation to find the distance the block slides before coming to rest.

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1. The friction force opposing motion is
Ff = M*g*cos27*Uk = 49.4 Newtons

Let X be the distance it travels down the ramp before it stops. When it stops,

(Work done against friction) = (Potential energy loss)+ (Kinetic energy loss)

49.4*X = (1/2)M*(1.52)^2 + M*g*sin27*X

Solve for X

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posted by drwls

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