hydrogen peroxide (H2O2) decomposes into water and oxygen. what amount of hydrogen peroxide is necessary to produce 24g of oxygen.
balance the equation. how many moles does it take to make one mole of O2? How many moles of O2 do you have?
To determine the amount of hydrogen peroxide (H2O2) necessary to produce 24g of oxygen, we first need to calculate the molar mass of hydrogen peroxide and oxygen.
The molar mass of hydrogen peroxide (H2O2) can be calculated by adding up the atomic masses of hydrogen (H) and oxygen (O). The atomic mass of hydrogen is approximately 1 g/mol, and the atomic mass of oxygen is approximately 16 g/mol.
Molar mass of H2O2 = (2 * atomic mass of hydrogen) + (2 * atomic mass of oxygen)
= (2 * 1 g/mol) + (2 * 16 g/mol)
= 2 g/mol + 32 g/mol
= 34 g/mol
Since one mole of hydrogen peroxide decomposes into one mole of oxygen, we can use the molar mass of oxygen to calculate the amount of hydrogen peroxide.
Molar mass of oxygen = 16 g/mol
Now, we can set up a proportion to find the amount of hydrogen peroxide required.
Mass of oxygen (given) / Molar mass of oxygen = Mass of hydrogen peroxide / Molar mass of hydrogen peroxide
Substituting the values into the equation:
24g / 16 g/mol = Mass of hydrogen peroxide / 34 g/mol
Simplifying the equation:
1.5 mol = Mass of hydrogen peroxide / 34 g/mol
To find the mass of hydrogen peroxide, rearrange the equation:
Mass of hydrogen peroxide = 1.5 mol * 34 g/mol
Mass of hydrogen peroxide = 51 g
Therefore, you would need 51 grams of hydrogen peroxide to produce 24 grams of oxygen.