what mass of hydrogen will react with 25g of oxygen to produce water?
Here is a sample stoichiometry problem.
Just follow the steps. http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the mass of hydrogen needed to react with oxygen and produce water, we first need to balance the chemical equation for the reaction.
The balanced equation for the reaction between hydrogen and oxygen to form water is:
2H₂ + O₂ → 2H₂O
From the balanced equation, we can see that for every 2 moles of hydrogen (H₂) reacting, we need 1 mole of oxygen (O₂) to produce 2 moles of water (H₂O).
Now, let's calculate the molar masses of hydrogen (H₂) and oxygen (O₂).
The molar mass of hydrogen (H₂) is approximately 2 grams/mole (1 gram/mole for each hydrogen atom).
The molar mass of oxygen (O₂) is approximately 32 grams/mole (16 grams/mole for each oxygen atom).
Now, let's use these molar masses to calculate the required mass of hydrogen to react with 25 grams of oxygen.
1. Calculate the number of moles of oxygen:
moles of O₂ = mass of oxygen / molar mass of oxygen
moles of O₂ = 25 grams / 32 grams/mole ≈ 0.78125 moles
2. Since the reaction ratio is 2:1 (2H₂:O₂), we need half the number of moles of oxygen for hydrogen:
moles of H₂ = 0.78125 moles / 2 ≈ 0.3906 moles
3. Calculate the mass of hydrogen needed:
mass of H₂ = moles of H₂ x molar mass of hydrogen
mass of H₂ = 0.3906 moles x 2 grams/mole ≈ 0.7813 grams
Therefore, approximately 0.7813 grams of hydrogen will react with 25 grams of oxygen to produce water.