How many moles of solute are present in 155 mL of 0.30 M NaNO3?
To determine the number of moles of solute present in a solution, you need to use the formula:
moles = molarity × volume
Given:
Molarity (M) = 0.30 M
Volume (V) = 155 mL
First, convert the volume from milliliters (mL) to liters (L). Since 1 L = 1000 mL, divide the volume by 1000:
Volume (V) = 155 mL ÷ 1000 = 0.155 L
Now, substitute the values into the formula:
moles = 0.30 M × 0.155 L
Calculating:
moles = 0.0465 moles
Therefore, there are 0.0465 moles of NaNO3 present in 155 mL of 0.30 M NaNO3.