Having trouble with this one. Thank you.
Graph the equation and identify the y - intercept. y = 4/3x+2. (0,?)
Thank you
when x is zero,y intercept is ....2
Great. Thank you
Hold on. I actually need to graph this. What I did was go up vertically to 2 on the y axis, however the graph does not seem to be complete. The second answer for the horizontal line or x axis is (-2,0)?? Could that be correct??
To graph the equation y = (4/3)x + 2 and identify the y-intercept, you can follow these steps:
1. Start by plotting the y-intercept: The y-intercept is the point where the graph intersects the y-axis. In the equation y = (4/3)x + 2, the y-intercept is represented by the constant term, which is 2. So, the y-intercept is the point (0, 2).
2. Determine the slope: The coefficient of x in the equation y = (4/3)x + 2 represents the slope of the line. In this case, the slope is 4/3. The slope indicates how steep the line is and in which direction it moves.
3. Use the slope to find other points on the graph: Since the slope is 4/3, you can interpret this as "for every 3 units horizontally, go up 4 units vertically" or "for every 4 units vertically, go right 3 units."
Start from the y-intercept (0, 2). To find the next point, move 3 units to the right (since the slope is 4/3). This will bring you to the point (3, 2 + 4) or (3, 6). Plot this point on the graph.
4. Connect the points: Now that you have two points, (0, 2) and (3, 6), you can draw a straight line passing through these points to represent the equation y = (4/3)x + 2.
Therefore, the graph of the equation y = (4/3)x + 2 would look like a straight line passing through the points (0, 2) and (3, 6).
To obtain the y-coordinate at the point (0,?), substitute x = 0 into the equation. Hence:
y = (4/3)(0) + 2
y = 0 + 2
y = 2
So, the y-coordinate at the point (0,?) is 2.