let sin theta = -7/25 with theta in QIV find sec (2theta)
if sinØ = -7/25 in IV, then
cosØ = +24/25
sec 2Ø = 1/cos 2Ø
= 1/(cos^ Ø - sin^2 ‚
= 1/(576/625 - 49/625)
= 625/527
cosØ = +24/25
sec 2Ø = 1/cos 2Ø
= 1/(cos^ Ø - sin^2 ‚
= 1/(576/625 - 49/625)
= 625/527