How many moles of O are in 13.0 mol Fe(NO3)3?
can you please find this using dymensional analysis and show me how you worked it? Thans
13.0 moles Fe(NO3)3 x [9 Oxygen atoms/1 mole Fe(NO3)3] = 13.0 x 9 = ?? which is what Bob Pursley wrote a couple of days ago when I was reading his answers.
Sure! To find the number of moles of oxygen (O) in 13.0 mol of Fe(NO3)3, we can use dimensional analysis.
First, let's find the molar ratio between O and Fe(NO3)3. From the chemical formula Fe(NO3)3, we can see that there are 3 moles of oxygen (O) for every 1 mole of Fe(NO3)3.
Now, we can set up the dimensional analysis as follows:
(13.0 mol Fe(NO3)3) x (3 mol O / 1 mol Fe(NO3)3)
The "mol Fe(NO3)3" units will cancel out, leaving us with the desired units of moles of oxygen (O).
Calculating this:
= 13.0 mol Fe(NO3)3 x (3 mol O / 1 mol Fe(NO3)3)
= 13.0 mol Fe(NO3)3 x 3
= 39.0 mol O
Therefore, there are 39.0 moles of oxygen (O) in 13.0 moles of Fe(NO3)3.
Sure! We can use dimensional analysis to calculate the number of moles of oxygen (O) in 13.0 mol of Fe(NO3)3.
To start, we need to gather some information:
1. The molar mass of Fe(NO3)3:
Fe: 55.85 g/mol
N: 14.01 g/mol
O: 16.00 g/mol
Multiply the molar masses by the respective subscripts:
Fe: 1 x 55.85 g/mol = 55.85 g/mol
N: 3 x 14.01 g/mol = 42.03 g/mol
O: 9 x 16.00 g/mol = 144.00 g/mol
Add up the individual masses to get the molar mass:
55.85 g/mol + 42.03 g/mol + 144.00 g/mol = 241.88 g/mol
Next, we'll use dimensional analysis to convert 13.0 mol of Fe(NO3)3 to moles of O:
1 mol Fe(NO3)3 = 6 moles O
So, the conversion factor is 6 moles O / 1 mole Fe(NO3)3.
Now let's apply the dimensional analysis:
13.0 mol Fe(NO3)3 x (6 mol O / 1 mol Fe(NO3)3)
The units "mol Fe(NO3)3" will cancel out, leaving us with:
13.0 mol Fe(NO3)3 x 6 mol O = 78.0 mol O
Therefore, there are 78.0 moles of oxygen (O) in 13.0 moles of Fe(NO3)3.
Sure, I can help you with that! Let's start by writing out the chemical formula for iron(III) nitrate: Fe(NO3)3.
To find the number of moles of oxygen (O) in 13.0 mol of Fe(NO3)3, we need to first determine the mole ratio between Fe(NO3)3 and O. By looking at the formula, we can see that there are 3 moles of O for every 1 mole of Fe(NO3)3.
Now, let's set up the dimensional analysis calculation:
13.0 mol Fe(NO3)3 ? mol O
--------------------------------------------
1 mol Fe(NO3)3 3 mol O
To find the number of moles of O, we can cross multiply and divide:
? mol O = (13.0 mol Fe(NO3)3) x (3 mol O / 1 mol Fe(NO3)3)
Simplifying this expression gives us:
? mol O = (13.0 mol) x (3 mol O) / (1 mol)
Calculating this equation, we find:
? mol O = 39.0 mol O
So, there are 39.0 moles of oxygen (O) in 13.0 moles of Fe(NO3)3.
Now, just to add a little humor: Why did the mole go to art class? Because it wanted to learn how to make chemical bonds more visually appealing!