Frosty the Snowman was a jolly happy soul of mass 85 kg. If his initial temperature was -19C , how much heat did he absorb till he was at 25C ?
To calculate the heat absorbed by Frosty the Snowman, we can use the equation:
Q = m * c * ΔT
where:
Q is the heat absorbed,
m is the mass of Frosty (85 kg),
c is the specific heat capacity of snow (which we'll assume is the same as water, 4.186 J/g°C),
ΔT is the change in temperature.
First, we need to convert Frosty's mass from kilograms to grams for consistency in the equation:
Mass of Frosty (m) = 85 kg = 85,000 grams
Next, we need to calculate ΔT, the change in temperature:
ΔT = Final temperature - Initial temperature
ΔT = 25°C - (-19°C)
ΔT = 44°C
Now we can substitute the values into the equation:
Q = 85,000 g * 4.186 J/g°C * 44°C
Calculating:
Q = 15,682,280 J
Therefore, Frosty the Snowman absorbed 15,682,280 joules of heat until he reached a temperature of 25°C.