In a very simple model of the lower atmosphere, air has a constant density of 1.22 kg/m3. How much would the air pressure change over a height difference of 100 m?
change in pressure=density*length*gravity
To determine how much the air pressure would change over a height difference of 100m in a very simple model of the lower atmosphere, we can use the concept of hydrostatic pressure.
The hydrostatic pressure is given by the equation:
P = ρ * g * h
Where:
P is the pressure,
ρ is the density of the air,
g is the acceleration due to gravity, and
h is the height difference.
Given that the air has a constant density of 1.22 kg/m3, the height difference is 100m, and the acceleration due to gravity is approximately 9.8 m/s2, we can substitute these values into the equation:
P = 1.22 kg/m3 * 9.8 m/s2 * 100m
P = 1196 Pa
Therefore, the air pressure would change by 1196 Pascal over a height difference of 100m in this simplified model of the lower atmosphere.