25 ml HCl x 1L/1000mL x .200HCl/1L = .005 mol HCl.
Using the balanced equation from this, how many moles of NaOh will you need to completely neutralize the HCl?
The neutralization equation is
HCl + NaOH ==> NaCl + H2O
0.005 mole HCl will require 0.005 mol NaOH.
To determine the number of moles of NaOH needed to completely neutralize the HCl, we will use the balanced equation for the reaction between HCl and NaOH. The balanced equation is:
HCl + NaOH → NaCl + H2O
From the balanced equation, we can see that the stoichiometric ratio between HCl and NaOH is 1:1. This means that for every 1 mole of HCl, we need 1 mole of NaOH to neutralize it.
Since you have calculated that you have 0.005 moles of HCl, you will need an equal amount of NaOH to neutralize it. Therefore, you will need 0.005 moles of NaOH.