If you add 23.5g of NaCl to 1.2 kg of water, what will be the boiling point and the freezing point of the new solution? (Kf=1.86, Kb=0.52)
(Please show work, I appreciate everything)
freezing.
moles = grams/molar mass
Substitute and solve for moles NaCl.
molality = moles/kg solvent.
Substitute and solve for molality.
delta T = i*Kf*molality
Substitute and solve for delta T and convert to freezing point. i for NaCl = 2.
boiling point.
You can use the calculation above for moles; the work is already done.
You can use the calculation above for molality; the work is already done.
delta T = i*Kb*molality
Substitute and solve for delta T and convert to boiling point. i for NaCl = 2.
Post your work if you get stuck.