What mass of H2O is required to form 1.2 L of O2 at a temperature of 310 K and a pressure of 0.950 atm?
2H2O (l) ---> 2H (g) + O2 (g)

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  1. I have corrected the equation.

    2H2O(l) ---> 2H2 (g) + O2 (g)

    Use PV = nRT to convert 1.2 L of O2 at the conditions listed to moles. Solve for n.
    Using the coefficients in the balanced equation, convert moles of O2 to moles H2O.

    Convert moles H2O to grams. g = moles x molar mass.

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