When I'm rounded to the nearest 10 , I'm 600. The digit in my tens place is 1 more than my ones digit. Who am I?
Which of these numbers fit?
595, 596, 597, 598, 599, 600, 601, 602, 603, 604
598.
To find the number, let's follow these steps:
Step 1: Identify the tens and ones digits.
Since you are rounded to the nearest 10 and the number is 600, we know that the number falls between 595 and 605.
Step 2: Determine the relationship between the tens and ones digits.
The question states that the digit in the tens place is 1 more than the digit in the ones place. Let's say the ones digit is x, then the tens digit will be (x + 1).
Step 3: Formulate the equation.
The number can be written as (x + 1)x0. For example, if the ones digit is 4, then the tens digit is 5. So, the number is 540.
Therefore, our equation is (x + 1)x0 = 600.
Step 4: Solve the equation.
(x + 1)x0 = 600
To solve this equation, we need to find the value of x that satisfies the equation.
Dividing both sides of the equation by 10:
(x + 1) = 60
Subtracting 1 from both sides of the equation:
x = 59
Step 5: Find the final number.
Now that we have found the value of x (59), we can substitute it back into the original equation to find the number.
The number is (59 + 1) × 10 = 600.
Therefore, the number you are looking for is 600.