How many moles of O are in 13.5 mol Fe(NO3)3?
i got 7.32e25 but soon realized that is totally wrong.
moles of that atom,O:
FeN3O9. Looks like nine moles of O for each mole of ferric nitrate.
what is 9*13.5
thanks so much!
To find out how many moles of oxygen (O) are in 13.5 mol Fe(NO3)3, we need to consider the molecular formula of Fe(NO3)3.
In one molecule of Fe(NO3)3, there are three nitrate ions (NO3-), each containing one oxygen atom. So, we have a total of three oxygen atoms per Fe(NO3)3 molecule.
Now, we can calculate the number of moles of oxygen by multiplying the number of moles of Fe(NO3)3 by the number of oxygen atoms per Fe(NO3)3 molecule.
Number of moles of O = (Number of moles of Fe(NO3)3) x (Number of O atoms per Fe(NO3)3 molecule)
Number of moles of O = 13.5 mol Fe(NO3)3 x 3 mol O/mol Fe(NO3)3
Number of moles of O = 13.5 mol Fe(NO3)3 x 3 mol O/1 mol Fe(NO3)3
Number of moles of O = 40.5 mol O
Therefore, there are 40.5 moles of O in 13.5 mol Fe(NO3)3.