A car is moving such that its kinetic energy is 2.20×105 J. The car accelerates and the engine does 2.10×105 J of work to accelerate the car. What is the final kinetic energy of the car? Ignore energy lost to friction.

(Your answer must be accurate to at least 1%. Give your answer to at least three significant figures.)

What is 2.20E5+2.1E5 ?

To find the final kinetic energy of the car, we can use the work-energy principle, which states that the work done on an object equals the change in its kinetic energy.

The initial kinetic energy of the car is 2.20×105 J, and the work done by the engine to accelerate the car is 2.10×105 J.

According to the work-energy principle, the change in kinetic energy is equal to the work done on the object. Therefore, the final kinetic energy (Kf) is given by:

Kf = Ki + Work

where Ki is the initial kinetic energy and Work is the work done.

Plugging the given values into the equation, we have:

Kf = 2.20×105 J + 2.10×105 J

Kf = 4.30×105 J

Therefore, the final kinetic energy of the car is 4.30×105 J.