How many grams of oxygen gas (O2) will it take to oxidize 1 pound of iron metal? Explain.
We need to start with a balanced equation. So you need to balance
Fe + O2 -> Fe2O3
(asuming the oxide produced is Fe2O3)
next convert 1 lb to grams
1 pound = 453.6 grams
next work out the number of moles of Fe
atomic mass = 55.8
so number of moles =453.6 g/55.8 g mole^-1
the equation will tell you how many moles of O2 react with one mole of Fe, hence calculate the number of moles of O2 that react with
453.6 g/55.8 g mole^-1
of Fe
One mole of O2 has molar mass of 32 g mole^-1
hance calculate the mass (grams) of O2 needed.
454 gr iron in 1 lb
55.847 g/mol weight FE
454/55.847 8.129353 moles of iron
ratio is 1 Fe to 2 O
8.13 x3 24.39 div 4 6.0975 moles of O2
6.0975 x 32g/mol 195.12 of oxygen required
Is this correct?
To determine the number of grams of oxygen gas required to oxidize 1 pound of iron metal, we can follow these steps:
1. Convert the mass of iron from pounds to grams: Since we know that 1 pound is equal to approximately 453.592 grams, we can convert 1 pound of iron to grams by multiplying it by the conversion factor:
1 pound * 453.592 grams/pound = 453.592 grams
2. Write a balanced chemical equation for the oxidation of iron (Fe) by oxygen (O2): The balanced equation is:
4Fe + 3O2 → 2Fe2O3
3. Determine the molar mass of oxygen gas (O2): The molar mass of one oxygen molecule is approximately 32 grams/mol (16 grams per oxygen atom).
4. Calculate the number of moles of oxygen gas required: From the balanced equation, we can see that it takes 3 moles of oxygen gas to react with 4 moles of iron. Therefore, the molar ratio of oxygen gas to iron is 3/4. We can calculate the moles of oxygen gas as follows:
Moles of oxygen gas = (453.592 grams of iron * 1 mole of iron / molar mass of iron) * (3 moles of oxygen gas / 4 moles of iron)
Remember to use the molar mass of iron (Fe) to convert grams of iron to moles.
5. Convert moles of oxygen gas to grams: Finally, multiply the moles of oxygen gas by the molar mass of oxygen gas to get the mass in grams:
Mass of oxygen gas = Moles of oxygen gas * molar mass of oxygen gas
By following these steps, you can determine the number of grams of oxygen gas required to oxidize 1 pound of iron metal.