i have absolutely no idea how to solve this. can anyone help me, please?
log2(3x-1)-log2(x-1)-log2(x+1)=0 log2[(3x-1)/(x-1)(x+1)]=0 remove the log2 [(3x-1)/(x-1)(x+1)]= 2^0 = 1 solve for x I got x=3
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