Calculate the mass of ethanol required to heat 200mL of water from 21 degrees celcius to 45 degress celcius
To calculate the mass of ethanol required to heat 200 mL of water from 21 degrees Celsius to 45 degrees Celsius, you need to know the specific heat capacity of ethanol and the heat transfer equation.
The specific heat capacity of ethanol is approximately 2.44 J/g°C. This means that it takes 2.44 joules of energy to raise the temperature of 1 gram of ethanol by 1 degree Celsius.
First, you need to calculate the amount of heat energy required to raise the temperature of water from 21 to 45 degrees Celsius. This can be done using the heat transfer equation:
Q = mcΔT
Where:
Q is the heat energy (in joules)
m is the mass of the substance (in grams)
c is the specific heat capacity (in J/g°C)
ΔT is the change in temperature (in degrees Celsius)
Plugging in the values for water:
Q = (200 g) * (4.18 J/g°C) * (45°C - 21°C)
Q = (200 g) * (4.18 J/g°C) * (24°C)
Q = 20,064 J
Now that you know the amount of heat energy required, you can calculate the mass of ethanol needed to provide this amount of energy using the specific heat capacity of ethanol:
Q = mcΔT
Rearranging the equation to solve for mass:
m = Q / (cΔT)
Plugging in the values for ethanol:
m = 20,064 J / (2.44 J/g°C * 24°C)
m = 343.5 g
Therefore, approximately 343.5 grams of ethanol is required to heat 200 mL of water from 21 degrees Celsius to 45 degrees Celsius.