4x-8=12+6x
Please help! Thankss!
4x-8 - 6x + 8 =12+6x - 6x + 8
-2x = 20
now divide both sides by -2 to get
x = -10
4x-8=12+6x
-8=12+2x
-20=x
sorry.
2x=-20
x=-10
4x-8 = 12+6x
SUBTRACT 4x FROM BOTH SIDES
-8 = 12+2x
ADD 12 TO BOTH SIDES
4=2x
DIVIDE BOTH SIDES BY 2
2=x
To solve the equation 4x - 8 = 12 + 6x, we need to isolate the variable x on one side of the equation. Here's how you can do it step by step:
1. Start by simplifying both sides of the equation by combining like terms. On the left side, we have 4x - 8, and on the right side, we have 12 + 6x.
4x - 8 = 12 + 6x
2. To get rid of the 6x on the right side, we can subtract 6x from both sides of the equation. This will allow us to move all the x terms to the left side.
4x - 6x - 8 = 12
Simplifying this equation further, we have:
-2x - 8 = 12
3. Next, let's isolate -2x by adding 8 to both sides of the equation:
-2x - 8 + 8 = 12 + 8
Simplifying further, we get:
-2x = 20
4. Finally, to solve for x, we need to get rid of the coefficient -2. We can do this by dividing both sides of the equation by -2:
(-2x) / -2 = 20 / -2
Simplifying further, we obtain:
x = -10
So the solution to the equation 4x - 8 = 12 + 6x is x = -10.