I really need help factoring these special Trinomials.

This question really puzzled me. I thought I had it correct, but when I checked the answer at the back of the book, I was wrong, and so I would like to know what was it that I had done wrong.

This was the question:

x^2-4x+4

This is how I solved it:

x^2-4x+4
x^2-2x-2x+4
x(x-2)-2(x+2)
(x-2)(x+2)

- I could not get any further than this. I thought that this would be correct, but the actual answer is
(x-2)^2

How did they get that?
If there is an easier way to solve this, then can you please show me how. Cause solving things like I have above is difficult.

see

http://www.jiskha.com/display.cgi?id=1289262952

To factor the trinomial x^2-4x+4, you were on the right track initially by breaking down the term -4x into -2x and -2x. Then, you factored the common terms from each binomial to get x(x-2)-2(x+2). However, there was a small error in the next step.

Let's correct that and find the correct factored form:

x(x-2)-2(x+2)

Now, distribute the -2 to both terms inside the second parentheses:

x(x-2)-2x-4

Combine like terms:

x^2 - 2x - 2x - 4

Now, simplify further:

x^2 - 4x - 4

To find the correct factored form, we need to look for a perfect square trinomial. In this case, the first and last terms are both perfect squares: x^2 is (x^2)^1/2, and -4 is (-2)^2.

The perfect square trinomial can be factored into the square of a binomial. Here's how:

Start with the first term: x^2
This can be factored as (x)^2

Next, take the square root of the middle term -4, which is -2.

Now, write the factored form using the square of a binomial pattern:
(x - 2)^2

So, the correct factored form of the trinomial x^2-4x+4 is (x - 2)^2.

Alternatively, if you prefer an easier method to factor a perfect square trinomial like this, you can use the formula:

a^2 - 2ab + b^2 = (a - b)^2

In this case, a = x and b = 2. Plugging in these values into the formula, we get:

x^2 - 2(x)(2) + 2^2 = (x - 2)^2

So, using the formula, we can directly write the factored form as (x - 2)^2.

I hope this explanation helps you understand the correct solution and the easier method of factoring perfect square trinomials.