Hydrogen peroxide decomposes into water and oxygen. What amount of hydrogen peroxide is necessary to produce 1 kg of oxygen
Hydrogen peroxide is H2O2. First, convert the given amount (1kg O2) into moles. One mole of O2 is 2x16g = 32g. 1kg = 1000g. 1000/32 = 31.25, so we need 31.25 moles of O2. One mole of H2O2 contains one mole of O2, so we need 31.25 moles of H2O2 to produce 31.25 moles of O2. The problem asks for the "amount" of H2O2, which could be given in moles, but since O2 is given in kg I would convert the answer into kg. One mole of H2O2 is (2x1g)+(2x16g) = 34g, so 31.25 moles is 1062.5g or 1.0625kg.
To determine the amount of hydrogen peroxide necessary to produce 1 kg of oxygen, we need to know the balanced equation for the decomposition reaction. The balanced equation for the decomposition of hydrogen peroxide is:
2 H2O2 → 2 H2O + O2
From the equation, we can see that 2 moles of hydrogen peroxide decompose to produce 1 mole of oxygen.
The molar mass of hydrogen peroxide (H2O2) is approximately 34.02 g/mol (2 x 1.01 g/mol for hydrogen + 2 x 16.00 g/mol for oxygen).
To find the amount of hydrogen peroxide needed to produce 1 kg (1000 g) of oxygen, we can follow these steps:
1. Convert the mass of oxygen to moles. The molar mass of oxygen (O2) is approximately 32.00 g/mol.
Moles of oxygen = mass of oxygen / molar mass of oxygen
= 1000 g / 32.00 g/mol
= 31.25 mol (approx.)
2. Use the stoichiometric ratio from the balanced equation to determine the moles of hydrogen peroxide needed.
Moles of hydrogen peroxide = (moles of oxygen) / 1
= 31.25 mol / 1
= 31.25 mol (approx.)
3. Finally, convert the moles of hydrogen peroxide to grams using its molar mass.
Mass of hydrogen peroxide = moles of hydrogen peroxide × molar mass of hydrogen peroxide
= 31.25 mol × 34.02 g/mol
= 1062 g (approx.)
Therefore, approximately 1062 grams of hydrogen peroxide is necessary to produce 1 kg (1000 grams) of oxygen.