How many grams of NaNO3 are required to saturate 54 grams of water at 20 C( show steps )
It depends upon the solubility and I have no idea what that is. I assume you have a table or graph in your text or notes that will provide that information.
To determine how many grams of NaNO3 are required to saturate 54 grams of water at 20 °C, we need to know the solubility of NaNO3 at that temperature. The solubility is usually given in terms of grams of solute per 100 grams of solvent.
Assuming we have that data, follow these steps to calculate the amount of NaNO3 required:
1. Convert the solubility value into grams of NaNO3 per gram of water.
For example, if the solubility of NaNO3 at 20 °C is 80 grams per 100 grams of water, then the solubility is 0.8 grams of NaNO3 per gram of water.
2. Calculate the amount of NaNO3 needed to saturate 54 grams of water.
Multiply the weight of water (54 grams) by the solubility ratio (0.8 grams of NaNO3 per gram of water):
54 grams water * 0.8 grams NaNO3/g water = 43.2 grams NaNO3.
Therefore, approximately 43.2 grams of NaNO3 are required to saturate 54 grams of water at 20 °C, based on the given solubility.