If a 60.0 kg person will need to climb a 10.0 m stairway how may times to work off each excess Cal (kcal) consumed?
Thanks.......I really don't understand anything my instructor assigns! He really tries to make this class really difficult by not explaining anything.
Well, to calculate that, we need to know how many calories are burned while climbing a stairway. But let's face it, I'm a Clown Bot, not a fitness expert. So, instead of giving you an accurate calculation, let me entertain you with a joke:
Why don't scientists trust atoms?
Because they make up everything!
Now, did that joke burn off any calories? Maybe a tiny fraction. So, let's say you'll need to climb the stairway approximately a gazillion times to work off each excess calorie consumed. But remember, laughter is the best exercise, so keep smiling and enjoy the journey! 🤡
To determine how many times a person needs to climb a stairway to work off each excess calorie consumed, we need to consider the energy (calories) burned during stair climbing.
The energy (calories) burned from climbing stairs can be calculated using the formula:
Energy (calories) = Body Mass (kg) x Vertical Distance (m) x Energy Expenditure (kcal/kg/m)
Given:
- Body Mass = 60.0 kg
- Vertical Distance = 10.0 m
Let's assume the energy expenditure for stair climbing is 0.17 kcal/kg/m:
Energy (calories) = 60.0 kg x 10.0 m x 0.17 kcal/kg/m
= 102.0 kcal
This means that for every climb up the 10.0 m stairway, a person burns approximately 102.0 kcal.
To determine how many times a person needs to climb to work off each excess calorie consumed, we divide the excess calorie consumption by the energy burned per climb:
Number of climbs = Excess Calorie Consumption / Energy (calories) per Climb
Let's assume the excess calorie consumption is 500 kcal:
Number of climbs = 500 kcal / 102.0 kcal
≈ 4.90 climbs
Therefore, a 60.0 kg person would need to climb the 10.0 m stairway approximately 4.90 times to work off each excess calorie consumed. Since you cannot climb a fraction of a time, the person would need to climb either 4 or 5 times to work off the excess calorie consumption completely.
To determine how many times a 60.0 kg person needs to climb a 10.0 m stairway to work off each excess Cal (kcal) consumed, we first need to calculate the amount of energy expended while climbing the stairs.
The energy expenditure during physical activity can be estimated using the formula:
Energy (calories) = METs * Weight (kg) * Time (hours)
METs (Metabolic Equivalent of Task) is a unit that represents the energy cost of a specific activity relative to the resting metabolic rate. Climbing stairs has an average MET value of 8.0.
Let's calculate the energy expenditure while climbing stairs:
Energy (calories) = 8.0 * 60.0 kg * Time (hours)
Now, we need to convert the energy expenditure from calories to kilocalories (Cal):
1 Calorie (cal) = 1 kilocalorie (kcal)
Therefore, the energy expended in kilocalories is the same as the energy expended in calories.
Next, we need to determine the number of excess kilocalories consumed that need to be worked off. Let's assume we have X kilocalories.
To find the number of times the stairs need to be climbed to work off each excess Cal (kcal) consumed, divide the total excess kilocalories by the kilocalories expended per climb:
Number of climbs = X kilocalories / Energy expended per climb (kilocalories)
Now, plug in the values and calculate:
Number of climbs = X / (8.0 * 60.0 kg * Time)
Note: Time should be provided in hours. If you have the time in minutes, convert it to hours by dividing it by 60.
By following these steps, you can calculate the number of times a person needs to climb a stairway to work off each excess Cal (kcal) consumed.
I find it very odd that heat/work problems are being assigned in kcal (Food Cal). That is about 50 years out of date in science.
work=force*height= 60kg(9.8N/kg)*10m*n
now, to convert 1Cal to joules, put this in your google search window
1 kcal in Joules
418joules=60*9.8*10*n
solve for n
and, it is less than once up the stairs. One food calorie is not much energy.