What quantity of heat (in joules) is transferred when 25.0 g H2O(g) at 125C is converted to H2O at 35.0C
q = mass water x specific heat water x (Tfinal-Tinitial).
537.76
To calculate the quantity of heat transferred, we can use the heat transfer equation:
Q = m * C * ΔT
Where:
Q is the heat transfer in joules
m is the mass of the substance in grams
C is the specific heat capacity of the substance in J/g°C
ΔT is the change in temperature in °C
First, we need to find the specific heat capacity of water (H2O). The specific heat capacity of water is approximately 4.18 J/g°C.
Next, let's calculate the change in temperature:
ΔT = final temperature - initial temperature
ΔT = 35.0°C - 125.0°C
ΔT = -90.0°C
Since the change in temperature is negative, we can ignore the negative sign and use the absolute value of 90.0°C.
Now we can substitute the values into the equation:
Q = 25.0 g * 4.18 J/g°C * 90.0°C
Q ≈ 9405 J
Therefore, the quantity of heat transferred when 25.0 g of H2O(g) at 125°C is converted to H2O at 35.0°C is approximately 9405 joules.