an object is released from rest on a planet that has no atmosphere.the object falls freely for 3.46 m in the first second.what is the magnitude of the acceleration due to the gravity on the planet?
aqDS
To find the magnitude of the acceleration due to gravity on the planet, you can use the kinematic equation for free fall motion:
d = (1/2) * g * t^2
Where:
- d represents the distance traveled by the object (3.46 m in this case)
- g represents the acceleration due to gravity
- t represents the time interval (1 second)
Rearranging the equation and solving for g:
g = (2 * d) / t^2
Substituting the given values:
g = (2 * 3.46 m) / (1 s)^2
Calculating the magnitude of the acceleration due to gravity:
g = (2 * 3.46 m) / 1 s^2
g = 6.92 m/s^2
Therefore, the magnitude of the acceleration due to gravity on the planet is 6.92 m/s^2.