If 2.1 moles of CaCl2 are dissolved in enough water to make a 0.92-liter solution, what is the resulting molarity?
0.44 M CaCl2
0.70 M CaCl2
2.3 M CaCl2
3.0 M CaCl2
The definition is M = moles/L. Punch into the calculator and go. Remember to round to two significant figures.
0.70
molarity ,=no of mole of solute/volume in liter
2.1/0.92=2.28mole/l
To determine the molarity of a solution, you need to divide the number of moles of the solute by the volume of the solution in liters. In this case, we have 2.1 moles of CaCl2 dissolved in a 0.92-liter solution.
The formula for molarity (M) is:
Molarity (M) = Moles of Solute / Volume of Solution (in liters)
Plugging in the given values, we have:
Molarity (M) = 2.1 moles CaCl2 / 0.92 liters
Dividing 2.1 by 0.92 gives us a molarity of approximately 2.28 M CaCl2.
Therefore, the correct answer is 2.3 M CaCl2.