Based on the balanced equation,
C2H4 + 3O2 → 2CO2 + 2H2O
calculate the molecules of H2O formed when 135 molecules of O2 are reacted.
To calculate the number of molecules of H2O formed when 135 molecules of O2 are reacted, we can use the stoichiometric coefficients from the balanced equation.
From the balanced equation:
1 molecule of C2H4 reacts with 3 molecules of O2 to produce 2 molecules of CO2 and 2 molecules of H2O.
We are given that 135 molecules of O2 are reacted. We need to calculate the number of molecules of H2O formed.
Molecules of O2 reacted = 135
Ratio of O2 to H2O from the balanced equation = 3:2
To find the number of molecules of H2O:
Number of molecules of H2O = (Number of molecules of O2) * (Coefficients ratio of H2O to O2)
Number of molecules of H2O = 135 * (2/3)
Number of molecules of H2O = 90
Therefore, when 135 molecules of O2 are reacted, 90 molecules of H2O are formed.
To calculate the number of molecules of H2O formed when 135 molecules of O2 are reacted, we can use the balanced equation provided.
The balanced equation is:
C2H4 + 3O2 → 2CO2 + 2H2O
From the equation, we can see that for every 3 molecules of O2 reacted, 2 molecules of H2O are formed.
To find the number of molecules of H2O formed when 135 molecules of O2 are reacted, we can use a proportion:
(2 molecules H2O) / (3 molecules O2) = (x molecules H2O) / (135 molecules O2)
Solving for x, we can multiply both sides of the equation by 135 and then divide by 3:
x = (2 molecules H2O / 3 molecules O2) * 135 molecules O2
x = 90 molecules H2O
Therefore, when 135 molecules of O2 are reacted, 90 molecules of H2O are formed.