solve for x
2(e^-7x)=5
you will have to use natural logs
e^-7x = 2.5
ln (e^-7x) = ln 2.5
-7x(ln w) = ln 2.5
-7x = ln 2.5 , since ln e = 1
x = ln2.5/-7 = appr. -.1309
2(e^-7x)=5
e^-7x = 2.5
ln (e^-7x) = ln 2.5
-7x(ln w) = ln 2.5
-7x = ln 2.5 , since ln e = 1
x = ln2.5/-7 = appr. -.1309