How much work is required to stop an electron (m = 9.11*10^-31 kg) which is moving with a speed of 1.50×106 m/s?
76879 un
To find the work required to stop an electron, we can use the work-energy principle. The work done on an object is equal to the change in its kinetic energy.
The kinetic energy of an object can be calculated using the formula:
KE = (1/2) * m * v^2
Where KE is the kinetic energy, m is the mass, and v is the velocity.
Given:
Mass of the electron (m) = 9.11 * 10^-31 kg
Velocity of the electron (v) = 1.50 * 10^6 m/s
Substituting the values into the formula:
KE = (1/2) * (9.11 * 10^-31 kg) * (1.50 * 10^6 m/s)^2
Now, calculate KE using a calculator:
KE = (1/2) * (9.11 * 10^-31 kg) * (2.25 * 10^12 m^2/s^2)
KE ≈ 1.02775 * 10^-18 J
Therefore, the kinetic energy of the electron is approximately 1.02775 * 10^-18 J.
Since we want to stop the electron completely, the final kinetic energy will be zero. Therefore, the work done to stop the electron would be equal to the initial kinetic energy:
Work = KE = 1.02775 * 10^-18 J
Hence, approximately 1.02775 * 10^-18 J of work is required to stop the electron.