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How do you find the implicit differentiation of 2/x + 2/y = 5?

(-2/x^2) dx/dx - (2/y^2)dy/dx = 0

-(1/x^2) dx = (1/y^2) dy

dy/dx = -y^2/x^2

but y = 2x/(5x-2)
y^2 = 4x^2/(5x-2)^2
so
dy/dx = -4/(5x-2)^2

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