The following reaction consumes 2.15 kg of Co(g): Co(g) + H2O(g) --> CO2(g) + H2(g) How many total liters of gas are formed if the products are collected at STP?
Do you know the difference between Co and CO? I can't believe Co will produce CO. The alchemists should have known about this.
The following reaction consumes 2.15 kg of CO(g): CO(g) + H2O(g) --> CO2(g) + H2(g) How many total liters of gas are formed if the products are collected at STP?
Here is an example of a stoichiometry problem I've posted. Just follow the steps to find moles CO2 and moles H2O Then convert to liters by moles x 22.4 L/mole.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the total number of liters of gas formed, we need to calculate the number of moles of each gas and then use Avogadro's Law to convert moles to liters at STP (Standard Temperature and Pressure).
First, let's find the number of moles of Co(g) consumed in the reaction. We can do this by dividing the given mass of Co(g) by its molar mass. The molar mass of cobalt (Co) is 58.93 g/mol.
Moles of Co(g) = Mass of Co(g) / Molar mass of Co(g)
= 2.15 kg / (58.93 g/mol)
= 2150 g / (58.93 g/mol)
= 36.475 moles of Co(g)
Next, we need to find the stoichiometric ratios of the gases in the balanced equation. In this case, the coefficient of Co(g) is 1 and the coefficients of CO2(g) and H2(g) are also 1.
Using the coefficients, we can deduce that 1 mole of Co(g) produces 1 mole each of CO2(g) and H2(g).
Therefore, the moles of CO2(g) and H2(g) produced are also 36.475.
Now, let's use Avogadro's Law to convert the number of moles of gas to liters at STP. At STP, 1 mole of gas occupies 22.41 liters.
Liters of gas = Moles of gas * 22.41 L/mol
Liters of CO2(g) = 36.475 moles * 22.41 L/mol = 816.45975 L
Liters of H2(g) = 36.475 moles * 22.41 L/mol = 816.45975 L
The total number of liters of gas formed when the products are collected at STP is the sum of the liters of CO2(g) and H2(g):
Total liters of gas formed = Liters of CO2(g) + Liters of H2(g)
= 816.45975 L + 816.45975 L
= 1632.92 L
Therefore, the total number of liters of gas formed is 1632.92 L.