A spy in a speed boat is being chased down a river by government officials in a faster craft. just as the officials' boat pulls up next to the spy's boat both boats reach the edge of a 5.0meter waterfall. If the spies speed is 15m/s and the officials' speed is 26 m/s, how far apart will the two vessels be when they land below the waterfall?
Goodness.
time to fall 5 meters:
h=1/2 g t^2 solve for t on the waterfall drop.
distanceapart=(26-15)t
11.11
23
To find the distance between the two vessels when they land below the waterfall, we need to calculate the time it takes for both boats to reach the edge of the waterfall.
Let's assume that both boats start from the same point. Since the speed of the spy's boat is 15 m/s, and the speed of the officials' boat is 26 m/s, we can calculate how long it takes for both boats to reach the waterfall by using the formula:
time = distance / speed
For the spy's boat:
time = 5.0 m / 15 m/s = 0.33 seconds
For the officials' boat:
time = 5.0 m / 26 m/s = 0.19 seconds
Now, we need to find how far apart the two boats are when they land below the waterfall. Since the officials' boat has already caught up to the spy's boat when they reach the edge, they will continue descending together, maintaining the same distance. Therefore, the distance between the two boats when they land below the waterfall will be the same as it was when they reached the edge.
Thus, the two vessels will be 5.0 meters apart when they land below the waterfall.