A long jumper jumps with the initial velocity of 12.0 m/s at an angle of 20 degrees. what is the displacement of x?
the question his how long is she in the air?
Vertical:
hf=ho+Vi*t-4.9t^2, hf=ho=0, Vi=12Sin20 solve for t
Horizontal:
distance=V*t=12Cos20*t
To find the displacement in the x-direction, we need to decompose the initial velocity into its x and y components. The x-component (Vx) can be found using the formula:
Vx = V * cos(theta)
where V is the initial velocity (12.0 m/s) and theta is the angle (20 degrees).
Substituting the values, we have:
Vx = 12.0 m/s * cos(20 degrees)
Vx ≈ 11.32 m/s
Now, we can determine the displacement in the x-direction using the formula:
Displacement (x) = Vx * t
where t is the time the long jumper is in the air. However, the time is not provided in the question. So, in order to calculate the displacement, we need to know the time the long jumper is in the air or provide additional information.