# Algebra II

A train left Podunk and traveled north at 75 Km/h. Two hours later, another train left Podunk and traveled in the same direction at 100 km/h. How many hours had the first train traveled when the second train overtook it?

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1. You can solve it algebraically or you can set up a chart:

First train:
1 hr: 75 mi
2 hr: 150 mi
3 hr: 225 mi
-- Continue this chart

Second train:
1 hr: 100 mi
2 hr: 200 mi
3 hr: 300 mi
-- Continue this chart.

Compare the charts to see when they've both traveled the same distance, but the second train reached it in two hours less.

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👩‍🏫
Ms. Sue
2. distance = rate x time
A train rate = 75 km/hr

B train rate = 100 km/hr

distance traveled by A train =
75 x (t+2 hrs)

distance traveled by B train =
100 x t

Distance is the same so set them equal to each other.
75(t+2) = 100t
solve for t = time.

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3. i needhelp with solving systems of equetions algebrically

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4. Use the matrix method to solve:

x + 4y = 8

2x + y = 9

x = a0

y = a1

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5. your

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