A long jumper jumps with the initial velocity of 12.0 m/s at an angle of 20 degrees. what is the displacement of x?

To calculate the displacement in the x-direction, we need to separate the initial velocity into its horizontal and vertical components. The horizontal component of the initial velocity remains constant throughout the motion, while the vertical component is affected by gravity.

Given:
Initial velocity (v0) = 12.0 m/s
Angle (θ) = 20 degrees

To find the horizontal component (vx):
vx = v0 * cos(θ)
vx = 12.0 m/s * cos(20 degrees)

To find the vertical component (vy):
vy = v0 * sin(θ)
vy = 12.0 m/s * sin(20 degrees)

Since there is no acceleration in the x-direction (assuming air resistance is negligible), the displacement in the x-direction (Δx) is given by the formula:
Δx = vx * t
where t is the time of flight.

To solve for time of flight (t), we need some additional information. If you provide the total time of flight, we can proceed to calculate the displacement in the x-direction.