what is the acceleration of a boy on a skateboard if the unbalanced forward force on the boy is 15 N? The total mass of the boy and the skateboard in 58 kg
15/58
To find the acceleration of the boy on a skateboard, we can use Newton's second law of motion, which states that the acceleration of an object is equal to the force acting on it divided by its mass.
Given:
Unbalanced forward force on the boy = 15 N
Total mass of the boy and the skateboard = 58 kg
We can use the formula:
Acceleration (a) = Force (F) / Mass (m)
Plugging in the values:
Acceleration (a) = 15 N / 58 kg
Calculating this, we get:
Acceleration (a) ≈ 0.2586 m/s²
Therefore, the acceleration of the boy on a skateboard is approximately 0.2586 m/s².
To determine the acceleration of the boy on a skateboard, you can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. The formula for calculating acceleration is:
acceleration = net force / mass
In this case, the net force is given as 15 N, and the total mass of the boy and the skateboard is 58 kg. Plugging these values into the formula, we get:
acceleration = 15 N / 58 kg
Simplifying the calculation, the acceleration of the boy on the skateboard is approximately 0.26 m/s².