what is the magnitude of the excealaration that is produced when the bracks of a 2.4 times 10 to the 3 power Kg car apply to a 3.2 times to to the power of 3 N force to stop the car..?
To find the magnitude of the acceleration produced by the brakes, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass of the car (m) = 2.4 × 10^3 kg
Force applied by the brakes (F) = 3.2 × 10^3 N
We can rearrange Newton's second law to solve for acceleration (a):
F = m × a
Substituting the given values:
3.2 × 10^3 N = 2.4 × 10^3 kg × a
Now, divide both sides of the equation by the mass of the car:
a = (3.2 × 10^3 N) / (2.4 × 10^3 kg)
Now, perform the calculation:
a = 1.333 m/s^2 (rounded to three decimal places)
Therefore, the magnitude of the acceleration produced when the brakes are applied to the car is 1.333 m/s^2.