Sorry for the re-post but I really need to know this, but now I just want to know if the question is right.

A spring with a force of 5.2 N/m has a relaxed length of 2.45. When a mass is attached to the end of the spring and allowed to come to rest. the vertical length of the spring is 3.57m. Calculate the elastic potential energy stored in the spring.

I got 3.26144

from 1/2* 5.2*1.12^2

Please help.

Looks good to me, but do not give the answer to 6 places after the decimal point. Something like 3.26 is plenty.

Ok thanks for the advice, now I can go to sleep.

To determine if your answer is correct, we can go through the steps to calculate the elastic potential energy stored in the spring and compare the result.

The formula to calculate elastic potential energy stored in a spring is given by:

Elastic potential energy = (1/2) * k * x^2

Where:
k is the spring constant (force per unit displacement) in N/m, which is given as 5.2 N/m.
x is the displacement of the spring from its relaxed length, which is the difference between the vertical length of the spring and its relaxed length, 3.57 m - 2.45 m = 1.12 m.

Let's plug in the values into the formula:

Elastic potential energy = (1/2) * 5.2 N/m * (1.12 m)^2

Calculating this expression:

Elastic potential energy = 0.5 * 5.2 N/m * 1.2544 m^2

Elastic potential energy = 3.26144 N*m or Joules

Therefore, your answer of 3.26144 is correct. Well done!