how many moles of anhydrous MgSO4 are in 2.04grams of MgSO4
moles= massingrams/molmassMgSO4
mass: 2.04
molar mass of MgSO4: 24.3+32.1+16*4=120.4
moles= 2.04/120.4
= 0.0169mol
To find the number of moles of anhydrous MgSO4 in 2.04 grams of MgSO4, we can follow these steps:
1. Determine the molar mass of MgSO4: The molar mass of MgSO4 is calculated by adding the atomic masses of its constituent elements. The atomic masses of magnesium (Mg), sulfur (S), and oxygen (O) are approximately 24.31 g/mol, 32.07 g/mol, and 16.00 g/mol, respectively. There are four oxygen atoms in MgSO4, so we multiply the atomic mass of oxygen by 4. Adding these values gives us:
Molar mass of MgSO4 = (24.31 g/mol) + (32.07 g/mol) + (4 × 16.00 g/mol) = 120.37 g/mol
2. Calculate the number of moles: Divide the given mass of MgSO4 (2.04 grams) by its molar mass (120.37 g/mol) using the formula:
Number of moles = Mass / Molar mass
Number of moles = 2.04 g / 120.37 g/mol ≈ 0.0169 mol
Therefore, there are approximately 0.0169 moles of anhydrous MgSO4 in 2.04 grams of MgSO4.