please help !! A 10 kg sled is pulled horizontally by a force. If the coefficient of static friction is 0.3 , what force is needed to get the sled moving at a constant velocity?
1.87
To determine the force needed to get the sled moving at a constant velocity, we need to consider the forces acting on the sled. There are two main forces at play: the applied force and the force of static friction.
The force of static friction can be calculated using the equation:
f = μ * N
where f is the force of friction, μ is the coefficient of static friction, and N is the normal force. In this case, the normal force is equal to the weight of the sled, which can be calculated using the equation:
N = m * g
where m is the mass of the sled and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Given that the sled has a mass of 10 kg and the coefficient of static friction is 0.3, we can start by calculating the normal force:
N = m * g
N = 10 kg * 9.8 m/s^2
N = 98 N
Now we can calculate the force of friction:
f = μ * N
f = 0.3 * 98 N
f = 29.4 N
Since the sled is already at rest and we want to get it moving at a constant velocity, the force needed to overcome static friction must be equal to the force of static friction. Therefore, the force needed to get the sled moving at a constant velocity is:
Force = 29.4 N
To find the force needed to get the sled moving at a constant velocity, we need to consider the forces acting on the sled.
The main force involved in getting the sled moving is the force of static friction. The formula for static friction is given by:
Fs = μs * N
Where Fs is the force of static friction, μs is the coefficient of static friction, and N is the normal force.
In this case, the sled is being pulled horizontally, so the normal force is equal to the weight of the sled. The formula for the weight is given by:
N = m * g
Where m is the mass of the sled and g is the acceleration due to gravity.
Given that the mass of the sled is 10 kg and the coefficient of static friction is 0.3, we can substitute these values into the equations:
N = 10 kg * 9.8 m/s^2 = 98 N
Fs = 0.3 * 98 N = 29.4 N
Therefore, a force of 29.4 N is needed to get the sled moving at a constant velocity.