k so question is one you have all answered previously, 3 different forces acting on a single mass, in north south and east directions.
my particular forces are 11.3 N north, 20.4 N east, and 14.7 N south
so to figure out the direction of acceleration in degrees, you have to take the arctan of resultant S, over E.
so that would be arctan 3.4/20.4
though for some reason is not correct, am i doing everything right?
I have no idea what angle you are computing. The above is correct for the angle as measured S of E.
sorry, uhm so first I figured out the acceleration of the mass, which was 5.78m/s^2. Then it asks what is the direction of acceleration, if you take east to be zero degrees and counterclockwise to be positive
Lord. I gave you the angle S of E, you want it measured from E counterclockwise all the way around. Is is possible for you to draw the figure? angle=360-arctan( )
Do you need a tutor? This is all very basic stuff.
yeah, and that wasn't the right answer. Its why i was asking you, you tool.
Yes, you are correct in using the arctan function to determine the direction of acceleration in degrees. However, there seems to be an error in the values you provided.
Let's calculate the resultant of the forces first. To find the resultant, we need to calculate the sum of the forces acting in the north and south directions, as well as the sum of the forces acting in the east and west directions.
Given the forces you provided:
North force = 11.3 N
East force = 20.4 N
South force = 14.7 N
To find the total force in the north and south directions:
Total north force = 11.3 N
Total south force = 14.7 N
To find the net force in the east and west directions, we need to subtract the smaller force from the larger one:
Net east force = 20.4 N - 0 (no force in the west direction) = 20.4 N
Therefore, the resultant force in the north and south directions is 11.3 N - 14.7 N = -3.4 N (negative because it is in the opposite direction to the positive/north direction).
Now, to determine the direction of acceleration, you need to calculate the arctan of the resultant force south (opposite direction) divided by the resultant force east (which is not zero as mentioned earlier).
So, the correct calculation would be:
arctan(-3.4 N / 20.4 N) = -9.5 degrees.
Therefore, the direction of acceleration is approximately -9.5 degrees, considering that the angle is measured counterclockwise from the positive east direction.