Which of the following is not a one-electron atom
A) H
B) He+
C) Li2+
D) Be2+
E) O7+
I know that H, He+, Li2+ and Be3+ are. i can't seem to find out about Be2+ and O7+. How do I calculate it?
Look at the periodic table. Be is atomic number 4 meaning it has 4 protons and 4 electrons for the neutral atom. Take away two electrons to make it +2 ion leaves 2 electrons.
O is atomic number 8. It has 8 protons and 8 electrons. Take away 7 electrons and that leaves ?? electron.
Thanks! That was what I thought.
To determine whether Be2+ and O7+ are one-electron atoms, you need to understand the electronic structure of atoms and how to apply the rules of electron configuration.
First, let's talk about electron configuration. Electron configuration is the distribution of electrons in an atom or ion. It follows a specific pattern based on the filling order of orbitals, which are regions around an atom where electrons are likely to be found.
For neutral atoms, electron configuration can be determined based on the position of the atom in the periodic table. However, for charged ions like Be2+ and O7+, we need to consider the number of electrons gained or lost.
Now, let's tackle Be2+ (beryllium ion with a 2+ charge).
To find the electron configuration of Be2+, we need to start with the electron configuration of neutral beryllium (Be). Be has an atomic number of 4, so its electron configuration is 1s^2 2s^2.
When Be loses 2 electrons to form a 2+ ion, we remove the outermost 2s electrons. Therefore, the electron configuration of Be2+ becomes 1s^2.
Since Be2+ has only one electron, it can be considered a one-electron atom.
Next, let's discuss O7+ (oxygen ion with a 7+ charge).
For oxygen (O), the neutral atom has an atomic number of 8 and an electron configuration of 1s^2 2s^2 2p^4.
When O gains 7 electrons to form O7+, we need to add these electrons to the existing electron configuration. Therefore, the electron configuration of O7+ becomes 1s^2 2s^2 2p^4 3s^2 3p^6 4s^2 3d^10 4p^6 5s^2 4d^10 5p^6 6s^2 5d^10 6p^6 7s^2.
Counting the number of electrons in this configuration, we find that O7+ has a total of 58 electrons. Based on this information, we can conclude that O7+ is not a one-electron atom.
Therefore, the answer to your question is E) O7+, which is not a one-electron atom.
To calculate the electron configuration for ions, it is helpful to refer to the periodic table to determine the number of electrons in the neutral atom and then adjust for the charge of the ion by adding or subtracting electrons accordingly.