k so question is one you have all answered previously, 3 different forces acting on a single mass, in north south and east directions.

my particular forces are 11.3 N north, 20.4 N east, and 14.7 N south
so to figure out the direction of acceleration in degrees, you have to take the arctan of resultant S, over E.
so that would be arctan 3.4/20.4
though for some reason is not correct, am i doing everything right?

sorry for repeating I just want it to be noticed is all

Yes, you are on the right track to find the direction of acceleration. To calculate the direction, you can use the arctan function. However, when finding the resulting vector components, you need to add the forces in the x and y directions separately.

In this case, you have a force of 11.3 N acting north, a force of 20.4 N acting east, and a force of 14.7 N acting south. To find the resulting force components in the x and y directions, you can think of the north direction as positive in the y-axis and the east direction as positive in the x-axis.

First, consider the y-direction (north and south). The north force is positive (+11.3 N) and the south force is negative (-14.7 N). So, the resulting force in the y-direction is 11.3 N - 14.7 N = -3.4 N.

Next, consider the x-direction (east). The east force is positive (+20.4 N), and there is no force acting in the west direction. So, the resulting force in the x-direction is 20.4 N.

Now, you can use the arctan function to find the angle of the acceleration. It is important to note that you need to take the arctan of the y-component divided by the x-component (-3.4 N / 20.4 N) and use the appropriate signs.

The correct calculation for the direction of acceleration is:

arctan(-3.4 N / 20.4 N) ≈ -9.8° (rounded to one decimal place)

Therefore, the direction of acceleration is approximately 9.8° south of west.

Make sure to double-check your calculations and ensure that the units are consistent (e.g., converting any forces given in other units to Newtons).