A block slides down a frictionless plane having an inclination of 14.6°.
If the block starts from rest at the top and the length of this incline is 1.90 m, find the acceleration of the block.
can someone just help me out with the equation I should be using? i really want to understand it, but alas, i don't
The force of gravity directed down the plane is mgSinTheta
forcedownplane= mass*accelerationdownplane
solve for acceleration
To find the acceleration of the block sliding down the inclined plane, you can use the equation:
acceleration (a) = g * sin(θ)
Where:
g is the acceleration due to gravity (approximately 9.8 m/s^2).
θ is the angle of the incline (in radians).
In this case, the angle of the incline is given as 14.6°. To convert it to radians, you need to use the formula:
θ (in radians) = θ (in degrees) * (π / 180)
Let's plug in the values:
θ (in degrees) = 14.6°
θ (in radians) = 14.6 * (π / 180) ≈ 0.254 radians
Now, you can substitute the values into the equation for acceleration:
a = g * sin(0.254)
By substituting g = 9.8 m/s^2 and calculating sin(0.254), you can find the acceleration.