How long does it take for a deposit of $1400 to double at 10% compounded continuously?

To find out how long it takes for a deposit to double at 10% compounded continuously, we can use the continuous compound interest formula:

A = P * e^(rt)

Where:
A = the final amount (in this case, double the deposit, which is $2800)
P = the initial deposit ($1400)
e = the mathematical constant approximately equal to 2.71828
r = the interest rate (10% or 0.10)
t = the time (unknown)

Let's plug in the values and solve for t:

2800 = 1400 * e^(0.10t)

To isolate the exponential term, divide both sides of the equation by 1400:

2 = e^(0.10t)

Next, take the natural logarithm (ln) of both sides to get rid of the exponential:

ln(2) = ln(e^(0.10t))

Using the property of logarithms, we can bring the exponent down to the front:

ln(2) = 0.10t * ln(e)

Since ln(e) is equal to 1, the equation simplifies to:

ln(2) = 0.10t

Now, divide both sides by 0.10 to solve for t:

t = ln(2) / 0.10

Using a calculator, we can find the value of ln(2) to be approximately 0.6931:

t = 0.6931 / 0.10

t ≈ 6.931

Therefore, it takes approximately 6.931 years for a deposit of $1400 to double at a 10% interest rate when compounded continuously.

To find out how long it takes for a deposit to double at a given interest rate compounded continuously, you can use the formula for continuous compound interest:

A = P * e^(rt)

Where:
A = the final amount (in this case, double the initial deposit, $1400 * 2 = $2800)
P = the initial deposit ($1400)
e = the mathematical constant approximately equal to 2.71828
r = the interest rate (in decimal form, 10% = 0.10)
t = the time (in years)

Now, rearrange the formula to solve for t:

t = ln(A/P) / r

ln represents the natural logarithm function.

Let's substitute the values into the formula:

t = ln(2800/1400) / 0.10

Using a calculator or software, we can evaluate this expression:

t ≈ ln(2) / 0.10 ≈ 6.93147 / 0.10 ≈ 69.31 years

Therefore, it would take approximately 69.31 years for a deposit of $1400 to double at a continuous interest rate of 10%.

23 days